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0.24x^2-x+0.5=0
We add all the numbers together, and all the variables
0.24x^2-1x+0.5=0
a = 0.24; b = -1; c = +0.5;
Δ = b2-4ac
Δ = -12-4·0.24·0.5
Δ = 0.52
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{0.52}}{2*0.24}=\frac{1-\sqrt{0.52}}{0.48} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{0.52}}{2*0.24}=\frac{1+\sqrt{0.52}}{0.48} $
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